Question 1136089


given: the ellipse with equation

{{{x^2/100 +y^2/64 = 1}}}

=>{{{a^2=100}}}=>{{{a}}}=±{{{10}}}
=>{{{b^2=64}}}=>{{{b}}}=±{{{8}}}
{{{h=0}}}}
{{{k=0}}}}

{{{c=sqrt(a^2-b^2)}}}
{{{c=sqrt(100-64)}}}
{{{c=sqrt(36)}}}
{{{c}}}=±{{{ 6}}}

the center is at ({{{0}}},{{{0}}})

vertices at:(±{{{a}}},{{{0}}})

({{{10}}},{{{0}}}),({{{-10}}},{{{0}}})

foci at:(±{{{c}}},{{{0}}})

({{{6}}},{{{0}}}),({{{-6}}},{{{0}}})


answer is:
C.Center: (0, 0); Vertices: (-10, 0), (10, 0); Foci: (-6, 0), (6, 0)