Question 1136094



{{{(x-h)^2/a^2-(y-k)^2/b^2 = 1}}}

compare to your 

{{{x^2/9-y^2/16 = 1}}}


=> {{{h=0}}}, {{{k=0}}}, {{{a}}}=±{{{3}}}, {{{b}}}=±{{{4}}}

{{{c=sqrt(a^2+b^2)}}}

{{{c=sqrt(3^2+4^2)}}}

{{{c=sqrt(25)}}}

{{{c}}}=±{{{5}}}

so,

center: ({{{0}}},{{{0}}})

foci: ({{{c}}},{{{0}}})=({{{-5}}}, {{{0}}}) and ({{{5}}}, {{{0}}})

vertices: ({{{a}}},{{{0}}})=({{{-3}}}, {{{0}}})  and ({{{3}}},{{{ 0}}})


answer:Vertices: (± {{{3}}},{{{ 0}}}); Foci: (± {{{5}}},{{{ 0}}})