Question 1136032
please help me understand how to solve this equation. it is from a lecture not a homework problem, but I want to understand how he achieved the solution. 

the equation is 0.4=0.8(vgsq-1.2)^2  solve for vgsq

the answer is vgsq=1.907   
I was trying to get the same answer but I got 1.65 after I took the square root of vgsq. please help me understand this algebra step.
<pre>{{{matrix(1,3, .4, "=", .8(VGSQ - 1.2)^2)}}}
{{{matrix(1,3, .4/.8, "=", (VGSQ - 1.2)^2)}}} ----- Dividing each side by .8
{{{matrix(1,3, .5, "=", (VGSQ - 1.2)^2)}}} 
{{{matrix(1,3, sqrt(.5), "=", VGSQ - 1.2)}}} ------ Taking the square root of both sides
{{{highlight_green(matrix(1,8, VGSQ, "=", sqrt(.5) + 1.2, "=", "1.907106781,", rounded, to, highlight(1.907)))}}}