Question 1136029
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A horizontal cross section (a view from the top of the prism) will be a circle inscribed in an equilateral triangle.<br>
Whenever you are working a problem with equilateral triangles inscribed in circles, or circles inscribed in equilateral triangles, draw the lines in the triangle that divide the equilateral triangle into 6 30-60-90 right triangles.<br>
If you do that in your problem, you can use the given radius of the circle and your knowledge about the side lengths of 30-60-90 right triangles to find the area of the equilateral triangular base of the prism.<br>
Then the volume is that base, times the height of 12 that you already know.