Question 103666
 x^2 – 10x + 16 = 0
You can factor this equation into a form:
{{{(x+a)(x+b)=0}}}
where 
{{{a+b=-10}}}
{{{a*b=16}}}
When you look at factors of 16 (1,16),(2,8),(4,4), you can pick out the factor pair that sums to 10 that is (2,8). 
Now you just need to get the signs right. 
They need to sum to -10, so you can use -2 and -8 since 
{{{-2+(-8)=-10 }}}and {{{(-2)*(-8)=16}}}
So your equation becomes
{{{x^2-10x+16=(x+(-2))(x+(-8))=0}}}
{{{x^2-10x+16=(x-2)(x-8)=0}}}
{{{(x-2)=0}}} and {{{(x-8)=0}}} 
x=2 and x=8 make this equation true.