Question 1135951
25*125^2r = 25^3r+3   Please show steps and solution
<pre>If {{{matrix(1,3, 25(125)^(2r), "=", 25^(3r + 3))}}}, then:
{{{matrix(1,3, (5^2)(5^3)^(2r), "=", (5^2)^(3r + 3))}}}
{{{matrix(1,3, (5^2)(5)^(6r), "=", 5^(6r + 6))}}}
{{{matrix(1,3, 5^(2 + 6r), "=", 5^(6r + 6))}}}
2 + 6r = 6r + 6 ------- Bases are equal and so are their exponents
6r - 6r = 6 - 2
{{{0 <> 4}}}, so NO SOLUTIONS. <b><======= CORRECT ANSWER, considering the correct equation was solved</b>

You DON'T NEED LOGS or any complex calculations to solve this equation....just the laws of exponents! 
Using logs is just a waste of time and effort, unless you're requested to use logs, of course.