Question 1135952
Look at the probability instead of getting two colors the same
B: (5/12)(4/11)
R: (4/12)(3/11)
G: (3/12)(2/11)
That sum is (20+12+6)/132 or 38/132 or 19/66

The probability of getting two different colors is 1-(19/66) or 47/66 or 0.712