Question 1135939
well, .....


i got k = 2 and it appears to be correct.


here's my worksheet.


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in step 1 i copied the problem.


in step 2 i multiplied both sides of the equation by 36^(-2k-3)


in step 3 i converted 36^(-2k-3) to 36^(-2k) / 36^3 because they're equivalent.


in step 4 i divided 36 in the numerator into 36^3 in the denominator to get 36^2 in the denominator.


in step 5 i replaced (6 * 36)^(-2k) with 6^(-2k) * 36^(-2k) because they're equivalent.


in step 6 i divided both sides of the equation by 36^(-2k) which then removed 36^(-2k) from the equation because 36^(-2k) / 36^(-2k) = 1.


in step 7 i made 6^(-2k) equal to 1 / 6^(2k) because they're equivalent.


in step 8 i cross multiplied.


in step 9 i took the log of both sides of the equation to get log(36^2)( = log(6^(2k)) which then became 2 * log(36) = 2k * log(6) because log(x^a) = a*log(x).


in step 10 i divided both sides of the equation by log(6).


in step 11 i divided both sides of the equation by 2.


in step 12 i solved for k.


any questions how or why i got what i got, send email to dtheophilis@gmail.com.


in donfirmed by replacing k with 2 in the original equation and evaluated it to get 36 = 36.