Question 1135910
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<pre>
The hemisphere of the radius "r" has the volume


    {{{V[hs]}}} = {{{(1/2)*(4/3)*pi*r^3}}}.


The cone of the base radius "r" and the height "r" has the volume


    {{{V[cone]}}} = {{{(1/3)*pi*r^2*r}}} = {{{(1/3)*pi*r^3}}}.


The ratio of the two volumes is   {{{V[cone]/V[hs]}}} = {{{((1/3))/((1/2)*(4/3))}}} = {{{((1/3))/((2/3))}}} = {{{1/2}}}.       <U>ANSWER</U>
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Solved.