Question 1135796
.
 Twice a number +3 times  it’s reciprocal  is seven. Find the number 
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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Your formulation is &nbsp;<U>TOTALLY &nbsp;WRONG</U> &nbsp;since you &nbsp;INCORRECTLY &nbsp;USE &nbsp;"<U> it's </U>".


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;The correct formulation is


<pre>
              Twice a number +3 times  <U>its</U> reciprocal  is seven. Find the number
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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;It seems to me that it was explained &nbsp;<U>MANY &nbsp;TIMES</U> &nbsp;to you in this forum.
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Why you still did not learn it ?



<U>Solution</U>


<pre>
2x + {{{3/x}}} = 7    ===================>


2x^2 + 3 = 7x  ===================>


2x^2 - 7x + 3 = 0


{{{x[1,2]}}} = {{{(7 +- sqrt(7^2 - 4*2*3))/(2*2)}}} = {{{(7 +- sqrt(49-24))/4}}} = {{{(7 +- 5)/4}}}.


There are two answers:  The number   3  and  the number  {{{1/2}}}.
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