Question 1135748
The ordered pairs (using thousands of Sh.) are (4, 113) (7, 120) and (9, 124) 
put these into ax^2+bx+c=y
so 16a+4b+c=113
49a+7b+c=120 and
81a+9b+c=124

The first and second give 
-112a-28b-7c=-791
196a+28b+4c=480
84a-3c=-311

first and third give
-144a-36b-9c=-1017
324a+36b+4c=496
180a-5c=-521
those two become
420a-15c=-1555
-540a+15c=1563
-120a=8
a=-(1/15) or -0.0667
therefore 4b+c=113+16/15=114.0667 (114.1)
and (third) 9b+c=131.4
-5b=-17.3
b=3.46

c=100.26
the equation is -0.0667x^2+3.46x+100.26=f(x)
{{{graph(300,300,-5,25,-10,150, -0.0667x^2+3.46x+100.26)}}} in THOUSANDS of Sh.