Question 1135767
<pre>
We first calculate the probability of the complement event, which is to 
roll one of these 5 {1,2,4,5,6} 6 times in a row.  The probability of
that is {{{(5/6)^6=0.3348979767}}}

We subtract from 1 and get 0.6651020233 

OR:

On your TI-84 or TI-83 it's 6 trials, p=1/6, x value=0

binompdf(6,1/6,0)    <--find that @ 2ND VARS, scroll down to A:binompdf(

Press ENTER

0.3348979767

Subtract from 1,

0.6651020233

Edwin</pre>