Question 103625

{{{sqrt(2x-8)}}} Start with the given expression


Remember you cannot take the square root of a negative value. So that means the argument {{{2x-8}}} must be greater than or equal to zero (i.e. the argument <font size=4><b>must</b></font> be positive)


{{{2x-8>=0}}} Set the inner expression greater than or equal to zero


{{{2x>=0+8}}}Add 8 to both sides



{{{2x>=8}}} Combine like terms on the right side



{{{x>=(8)/(2)}}} Divide both sides by 2 to isolate x 




{{{x>=4}}} Divide



So that means x must be greater than or equal to 4

So here is the domain in interval notation: [4,*[Tex \LARGE \infty])