Question 1135750

{{{(x^2/9)+1}}} 

{{{(1/9)x^2+1}}} 

{{{(1/9)(x^2+9)}}} 

 {{{(1/9)(x^2+2abx+3^2)-(1/9)*2ab}}} 

in your case {{{a=1}}} and {{{b=3}}}, so add {{{6x}}}

 {{{(1/9)(x^2+6x+3^2)-(1/9)*6x}}}

 {{{(1/9)(x+3)^2-(6/9)x}}}

{{{(1/9)(x+3)^2-2x/3}}}

{{{(x^2/9)+1}}} can be made perfect square by adding {{{2x/3}}}