<PRE><B>Question 15167</B>
If there are 26 problems, let x = number right, and therefore the number wrong will be all the rest, which is 26-x.  The equation is due to the fact that 8 times the number right minus 5 times the number wrong equals zero.


8x - 5(26-x) = 0
8x - 130 + 5x = 0
13x - 130=0
13x -130 + 130 = 0+130
13x = 130
x= 10 Questions right
26-10 = 16 Questions wrong


Check:  $8*10 - $5*16 = 0


R^2 at SCC</PRE>