Question 1079104
G = Gabby's age now
L = Larry's age now
M = Megan's age now
<pr>
Gabby is 1 year more than twice Larry's age:
G = 2L + 1
<pr>
3 years from now, Megan will be 27 less than twice Gabby's age:
M + 3 = 2(G + 3) - 27
<pr>
Substitute G with 2L + 1:
M + 3 = 2((2L + 1) + 3) - 27
<pr>
Simplify the above:
M + 3 = 4L - 19
<pr>
Solve for L:
4L = M + 22
<pr>
L = (M + 22)/4
<pr>
4 years ago, Megan was 1 year less than 3 times Larry's age:
M - 4 = 3(L - 4) - 1
<pr>
Simplify the above:
M - 4 = 3L - 13
<pr>
Solve for M:
M = 3L - 9
<pr>
Substitute L with (M + 22)/4:
{{{M = 3((M + 22)/4) - 9}}}
<pr>
Simplify above:
{{{M = (3M + 66)/4 - 9}}}
<pr>
Solve for M:
{{{M = (3M + 66)/4 - 36/4}}}
<pr>
{{{M = (3M + 66 - 36)/4}}}
<pr>
{{{M = (3M + 30)/4}}}
<pr>
4M = 3M + 30
<pr>
M = 30
<pr>
M = Megan's age now = 30
<pr>
How old will Megan be 3 years from now?
<pr>
M + 3 = 30 + 3 = 33
<pr>
<b>Megan will be 33 three years from now.</b>
<pr>
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Just for kicks, their ages now:

Megan = 30
Larry = 13
Gabby = 27