Question 1135591
 {{{12}}}.......... {{{17}}}.......... {{{22}}}.......... {{{27}}} 

..........{{{5}}}.............{{{5}}}..........{{{5}}}

=> common difference is {{{d=5}}}, 

so, you add {{{5}}} to first term to get second term, add {{{5}}} to second term to get third term, and so on


so, in general,  you have arithmetic sequence and the formula for nth term will be

{{{a[n]=a[1]+(n-1)d}}}
{{{a[n]=12+(n-1)5}}}

and next term will be:

{{{a[n]=12+(5-1)5}}}

{{{a[n]=12+20}}}

{{{a[n]=32}}}

and so on...