Question 1135543
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Let x = capacity of a van and y = capacity of a bus.


From the condition, you have these two equations

    6x + 8y = 202   (1)
    4x + 2y =  68   (2)


In this case, I will apply the Elimination method. I multiply eq(2) by 4 (both sides), keeping equation (1) as is.


    6x + 8y = 202    (1')
   16x + 8y = 4*68   (2')


Now subtract eq(1') from eq(2').  The terms " 8y " will cancel each other, and you will get

    16x - 6x = 4*68 - 202,    or

    10x = 70   ================>  x = 70/10 = 7.


Now substitute this found value of x into eq(2) to find y. You will get


    4*7 + 2y = 68,

    2y = 68 - 28 = 40  ============>  y = 40/2 = 20.


<U>ANSWER</U>.  Van's capacity is 7 students;  bus' capacity is 20 students.
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Solved.