<PRE><B>Question 1135537</B>
&lt;br&gt;
With the traditional algebraic approach, you write and solve the equation that says x amount invested at 2%, plus ($55,000-x) invested at 10%, yields 5.2% on the total $55,000:&lt;br&gt;
{{{.02(x) + .10(55000-x) = .052(55000)}}}&lt;br&gt;
Straightforward algebra; but ugly numbers.  I&#39;ll let you finish the solution by that method.&lt;br&gt;
Here is a completely different method for solving this kind of &quot;mixture&quot; problem.  It is based on the fact that the ratio in which the two need to be mixed is exactly determined by where the mixture percentage lies between the two given percentages.&lt;br&gt;
Without any words of explanation, here are the required calculations:&lt;br&gt;
10-5.2 = 4.8
5.2-2 = 3.2
4.8:3.2 = 3:2&lt;br&gt;
The $55,000 must be split in two parts in the ratio 3:2 -- so $33,000 at one rate and $22,00 at the other.&lt;br&gt;
Since 5.2% is closer to 2% than it is to 10%, the larger portion needs to be at 2%.&lt;br&gt;
ANSWER: $33,000 at 2%; $22,000 t 10%</PRE>