Question 1135491
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The problem asks you to find the time " t " from this equation


    {{{A*e^(0.0281*t)}}} = 2A.


Cancel the factor A in both sides and take the natural logarithm of both sides.

You will get


    0.0281*t = ln(2).


So, the answer is  t = {{{ln(2)/0.0281}}} = 24.67 years, or about 24 years and 8 months.
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Solved.