Question 1135494
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First find the slope m, which is exactly the derivative of the function at x= 1:


    m = {{{(df)/(dx)}}} = {{{-2*(1/x)}}} = -2  at  x= 1.


You also need to know the value of the given function at x= 1. It is


    f(1) = 5 - 2*ln(1) = 5 - 2*0 = 5.


Thus the equation of the tangent line is


    y -5 = (-2)*(x-1),   or

    y - 5 = -2x + 2.


Now you can transform it to any form you want.  For example,  


    2x + y = 7.
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Answered and solved.