Question 1135470

	 
{{{abs(V)= 373}}}, {{{theta = 13}}}° {{{40}}}' ={{{theta = 13+40/60=13+2/3=41/3}}}

find:
{{{abs(V[x])}}}	=	 
{{{abs(V[y])}}}	=	 

{{{abs(V[x])=V*cos(theta) }}}
{{{abs(V[x])=373*cos(41/3) }}}
{{{abs(V[x])=373*0.97168674242}}}
{{{abs(V[x])}}}≈ {{{362.4}}}

{{{abs(V[y])=V*sin(theta)}}}
{{{abs(V[y])=373*sin(41/3)}}}
{{{abs(V[y])=373*0.236272881650641}}}
{{{abs(V[y])≈  {{{88.13}}}