Question 1135405
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Informally....<br>
(1) Count the "extra" 4 dimes and set them aside.  The remaining coins are equal numbers of nickels and dimes, with a total value of $1.75-$0.40 = $1.35.<br>
(2) Group the remaining coins in groups of one nickel and one dime each.  The value of each group is $0.15.<br>
(3) The number of groups worth $0.15 each needed to make the remaining $1.35 is 1.35/0.15 = 135/15 = 9; so there are 9 nickels and 9 dimes.<br>
(4) Now bring back in those 4 dimes you set aside at the beginning, to find that the number of nickels in his pocket is 9 and the number of dimes is 13.