Question 1135327
.


            The post by @josgarithmetic is, OBVIOUSLY, incorrect.


            The corrected version is below:



<pre>
When the car enters on the highway 8 minutes later, the track is exactly 8 miles ahead the car.


Starting from this time moment, the distance between them decreases at the rate (68-60) = 8 miles per hour.


So, to find the time "t", when catching will happen, you simply need to solve an equation



    (68-60)*t = 8   miles   (8 miles is the "head start" in this case)

    8t = 8,   giving  the <U>ANSWER</U>    t = {{{8/8}}} = 1 hour.
</pre>

Solved.


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See introductory lessons on Travel and Distance problems

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Travel and Distance problems for two bodies moving in the same direction (catching up)</A>

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