Question 1135322
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(1) Four sides of the original square nut, each 4cm by 6cm;
(2) The top and bottom of the original nut, with the hole drilled out -- 6cm by 6cm, minus the area of the circle with diameter 3.5cm (radius 1.75cm); and
(3) The lateral surface area of the cylindrical hole, with radius 1.75cm and height 4cm.<br>
Use your basic area formulas and add the pieces to get the total surface area.<br>
rectangle: length times width
circle: pi times radius squared
cylinder lateral surface: 2pi times radius times height