Question 1135279
If 2^x = 4^y = 8^z and (1/2x)+(1/4y)+(1/8z)=4, find the value of x.
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2^x = 2^(2y) = 2^(3z)

x = 2y = 3z

y = x/2

z = x/3
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(1/2x)+(1/4y)+(1/8z)=4
Is it (1/2)x or 1/(2x) ?
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1/(2x) + 1/(4*(x/2)) + 1/(8*(x/3)) = 4

1/(2x) + 1/(2x) + 1/(8x/3) = 4

1/2 + 1/2 + 3/8 = 4x

4x = 11/8
x = 11/32