Question 1135314
.
<pre>
2 questions from group A and 4 questions from group B  ( {{{C[5]^2*C[5]^4}}} ways)  PLUS

3 questions from group A and 3 questions from group B  ( {{{C[5]^3*C[5]^3}}} ways)  PLUS

4 questions from group A and 2 questions from group B  ( {{{C[5]^4*C[5]^2}}} ways).


The answer is the sum

    {{{C[5]^2*C[5]^4}}} + {{{C[5]^3*C[5]^3}}} + {{{C[5]^4*C[5]^2}}} = 

    10*5    +  10*10 +  5*10 = 200.


<U>ANSWER</U>.  200 ways.
</pre>

Solved.