Question 1135264
let a be the cost of an adult's ticket and c be the cost of a child's ticket, then
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1)  8a +5c = 180.50
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2) 12a +6c = 261
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solve equation 1 for a
:
8a = 180.50 -5c
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3) a = (180.50 -5c)/8
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substitute for a in equation 2
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12(180.50 -5c)/8 +6c = 261
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multiply both sides of = by 8
:
12(180.50 -5c) +48c = 2088
:
2166 -60c +48c = 2088
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-12c = -78
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c = 6.50
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Use equation 3 to find the value of a
:
a = (180.50 -5(6.50))/8 = 18.50
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cost of adult ticket is $18.50 and cost of child ticket is $6.50
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check the answer by substituting in equations 1 and 2
:
equation 1
:
8(18.50) +5(6.50) = 180.50
:
148 +32.50 = 180.50
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180.50 = 180.50
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equation 2
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12(18.50) +6(6.50) = 261
:
222 +39 = 261
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261 = 261
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answer checks
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