Question 14481
    x - 6y = 3....(1) ; 3x+ 2y = 1.....(2)  Let me explain elimination to you.there are  2 unknowns. we can easily solve if there is only 1 unknown.so we try to eliminate 1 unknown. say x .
see coefficient of x in both eqns.,1 and 3. find their lcm .it is 3. so multiply eqn.1 with 3 to get 3x and eqn.2 with 1 to get the same 3x.having made coefficient of x same in the 2 eqns.,add or subtract them to eliminate x.
 eqn.(1)*3....3x-18y=9......(3)
 eqn.(2)*1....3x+2y=1........(4)
 eqn(3)-eqn.(4)......-18y-2y=9-1...or -20y=8..or  y=-8/20=-2/5.
  now substitute this value of y in any eqn.say eqn.(1) to get x value
   x-6*(-2/5)=3...
   x=3-12/5=(15-12)/5 = 3/5.
  to check your answer substitute these 2 values of x and y in the given equations and check for compliance.
 Eqn.(1)....3/5 -6*(-2/5)= 3/5 +12/5 =15/5 = 3 =rhs ...ok.
 Eqn.(2)....3*(3/5)+2*(-2/5)=9/5-4/5=5/5=1 = rhs ...ok
  now i leave the second problem for you to do  as practice          
                         
    6x + -4y = 12
    9x  - 6y = 18