Question 1135070
<pre>{{{system(x = 10y + 44, xy = 3264)}}}

{{{(10y+44)y = 3264}}}

{{{10y^2+44y = 3264}}}

{{{10y^2+44y-3264=0}}}

Divide every term by 2

{{{5y^2+22y-1632=0}}}

{{{(y-16)(5y+102)=0}}}

y-16=0;     5y+102=0
   y=16;        5y=-102
                 y= -20.4, not a positive integer.

So y=16, substitute in

x = 10y + 44
x = 10(16) + 44
x = 160 + 44
x = 204

The positive integers are 16 and 204.

Edwin</pre>