Question 1135009
<a href="http://tinypic.com?ref=sxeohw" target="_blank"><img src="http://i65.tinypic.com/sxeohw.png" border="0" alt="Image and video hosting by TinyPic"></a>




 given:

The perimeter of {{{ABCD}}} is {{{36 }}}yards.

The length of {{{AB }}}is {{{34}}}¯???? the length of {{{AD}}}¯.(I think you put {{{34}}} by mistake)

 {{{AB }}} is probably {{{3/4}}}   the length of {{{AD}}}, I will go with that


{{{MN=(AB+CD)/2}}}

=>{{{AB+CD+AD+BC=36}}}

The line {{{MN}}} is the midline of {{{ABCD}}}. And the segment {{{MN}}} is the midsegment of {{{ABCD}}}. 

so,
 {{{AM = MD=4}}} => {{{AD=8}}}
{{{BN = NC =5}}}=>{{{BC=10}}}

=>{{{AB+CD+8+10=36}}}
=>{{{AB+CD=36-18}}}
=>{{{AB+CD=18}}}


{{{MN=(AB+CD)/2}}}

=>{{{MN=18/2}}}
=>{{{MN=9}}}


 since given that {{{AB }}} is {{{3/4}}}  the length of {{{AD=8}}}

=>{{{AB=(3/4)8}}}
=>{{{AB=6}}}

then =>{{{6+CD=18}}}=>{{{CD=18-6}}}=>{{{CD=12}}}


answer:

{{{MN=9}}}

{{{AB=6}}}
{{{CD=12}}}
 {{{AD=8}}}
{{{BC=10}}}

check the perimeter:

{{{AB+CD+AD+BC=36}}}
{{{6+12+8+10=36}}}
{{{36=36}}}