Question 1135025
What is	the combined probability of the	following events occurring: rolling 1 or
6 on a fair die, flipping 2 heads in a row on a fair coin, then rolling 2,3,4 or
5 on the same die.
<pre>
That's four events in succession:

A.  2 ways out of 6 that the die can fall successfully, a probability of 2/6 which
    reduces to 1/3.
B.  1 way out of 2 ways the fair coin can fall successfully the first time, a
    probability of 1/2.
C.  1 way out of 2 ways the fair coin can fall successfully the second time, also
    a probability of 1/2. 
D.  4 ways out of 6 that the die can fall successfully, a probability of 4/6 which
    reduces to 2/3.

For those 4 events to occur in succession, the probability is the product of the
probabilities, since they are independent events.

Answer: (1/3)(1/2)(1/2)(2/3) = 2/36 which reduces to 1/18.

Edwin</pre>