Question 1134980
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I read this as<br>
{{{log(8,(x))+log(4,(1/6)) = 1/3}}}<br>
Then<br>
{{{3log(8,(x))+3log(4,(1/6)) = 1}}}   (multiply by 3 to get a whole number on the right)<br>
{{{3*((1/3)log(2,(x)))+3*((1/2)log(2,(1/6))) = log(2,(2))}}}   (convert to log base 2)<br>
{{{log(2,(x))+(3/2)log(2,(1/6)) = log(2,(2))}}}<br>
{{{2*log(2,(x))+3*log(2,(1/6)) = 2*log(2,(2))}}}   (multiply by 2 again to clear fractions)<br>
{{{(x^2)((1/6)^3) = 2^2}}}    (convert to exponential form)
{{{x^2/6^3 = 2^2}}}
{{{x^2 = (2^2)(6^3) = (2^2)(2^3)(3^3) = (2^5)(3^3)}}}
{{{x = 12*sqrt(6)}}}