Question 1134928
.
According to Masterfoods, the company that manufactures M&M’s, 
12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. 

[Round your answers to three decimal places, for example: 0.123]


<pre>
(a)  Compute the probability that two randomly selected peanut M&M’s are both brown.


         P = 0.12*0.12 = 0.0144 = 0.014 (rounded as requested).    <U>ANSWER</U>

             ( 0.12 = 12% )



(b)  If you randomly select two peanut M&M’s, compute that probability that neither of them are orange.


         P = (1-0.12)*(1-0.12) = 0.88*0.88 = 0.7744 = 0.774 (rounded as requested).    <U>ANSWER</U>


             (My calculations should be clear to you without further explanations !)



(c)  If you randomly select two peanut M&M’s, compute that probability that at least one of them is orange.


         P = 0.23*0.23 + 0.23*(1-0.23)


             This time  <U>YOU</U>  make all necessary calculations and rounding on your own.


             Happy calculations !
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Who does not like &nbsp;M&M’s &nbsp;? &nbsp;?  &nbsp;&nbsp;&nbsp;&nbsp;(rhetoric question . . . )