Question 1134909

{{{1}}}, {{{3}}},{{{ 9}}}, {{{27}}}


if {{{n}}}={{{0}}},{{{1}}},{{{2}}},{{{3}}},.....

answer is:

{{{a[n] = 1 *3^n}}}

check
{{{a[0] = 1 *3^0=1}}}
{{{a[1] = 1 *3^1=3}}}
{{{a[2] = 1 *3^2=9}}}
{{{a[3] = 1 *3^3=27}}}