<PRE><B>Question 1134902</B>
Use the binomial probability formula
:
Probability (P) (k success in n trials) = nCk * p^k * (1-p)^(n-k), where p is the probability, nCk = n!/(k! * (n-k)!)
:
P(at least 1 of the children get the disease) = 1 - P(no children get the disease)
:
P(no children get the disease) = 5C0 * (0.30)^0 * (1-0.30)^(5-0) = 0.16807
:
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P(at least 1 of the children get the disease) = 1 - 0.16807 = 0.83193 is approximately 0.832
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:
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