<PRE><B>Question 1134830</B>
There are two possible events for the coin, namely, heads(H) and Tails(T)
:
there are six possible events for the die, namely, 1, 2, 3, 4, 5, 6
:
therefore, we have the following
:
(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6)
(T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)
:
there are 12 possible events
:
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