Question 1134833

?={{{x}}}

{{{9u/(u-4)=x/((u-4)(u+3))}}}.......simplify

{{{9u/cross((u-4))=x/(cross((u-4))(u+3))}}}

{{{9u/1=x/(u+3)}}}

{{{9u(u+3)=x}}}


=>{{{9u/(u-4)=(9u(u+3))/((u-4)(u+3))}}}