Question 1134828

let ? be {{{x}}}

{{{2y/(8y-3)=x/(64y-24)}}}

{{{2y/(8y-3)=x/8(8y-3)}}}.............simplify

{{{2y/cross((8y-3))1=x/8cross((8y-3))}}}

{{{2y/1=x/8}}}........cross multiply

{{{2y*8=x*1}}}

{{{x=16y}}}

then you have {{{2y/(8y-3)=16y/(64y-24)}}}