Question 1134827
let ? be {{{x}}}

{{{4w/(w-3)=x/((w-3)(w+6))}}}......cross multiply

{{{4w(w-3)(w+6)=x(w-3)}}}...simplify

{{{(4w*cross((w-3))(w+6))=x *cross((w-3))}}}


{{{x=4w(w+6)}}}


so, you have  {{{4w/(w-3)=4w(w+6)/((w-3)(w+6))}}}