Question 1134807
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You should of course know the method for solving this kind of problem using formal algebra.<br>
But if an algebraic solution is not required, you can solve the problem much more quickly simply by finding two numbers with a product of 592 in which one number is 11 less than 3 times the other.<br><pre>
592 = 2*296
    = 4*148
    = 8*74
    = 16*37  <--  that one works: 37 = 3(16)-11</pre>
Done!  The dimensions are 16 and 37