Question 1134805
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Arithmetic sequence with the first term 2 and the common difference 3.


{{{a[n]}}} = 2 + 3*(n-1).


The next two terms are  11  and  14.



When divided by 3, every term gives the remainder of 2.

Therefore, neither term of this sequence is a square, because a square of an integer number NEVER gives remainder 2 when divided by 3.


It gives the remainders 0 or 1, but never gives the remainder 2.
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