Question 1134789
given:
 right triangle {{{ABC}}} with

{{{ C = 90}}}° 
{{{A = 8}}}°{{{ 36}}}'={{{8.6}}}° 
{{{b = 4.752cm }}}


{{{B= 180-(90+8.6)}}}° 

{{{B= 180-98.6}}}° 

{{{B= 81.4}}}° 

{{{B}}}={{{81}}}°{{{24}}}'



{{{sin(A)/a=sin(B)/b}}}

{{{sin(8.6)/a=sin(81.4)/4.752}}}

{{{0.149535/a=0.988756/4.752}}}

{{{0.149535/a=0.20807154882}}}

{{{a=0.149535/0.20807154882}}}

{{{a=0.719cm}}}


c= cm 


{{{sin(A)/a=sin(C)/c}}}

{{{sin(8.6)/0.719=sin(90)/c}}}

{{{0.149535/0.719=1/c}}}

{{{0.207976356=1/c}}}

{{{c=1/0.207976356}}}

{{{c=4.808cm}}}

check using Pythagoras theorem:

{{{c^2=a^2+b^2}}}

{{{4.808^2=0.719^2+4.752^2}}}

{{{23.116864=0.516961+22.581504}}}

{{{23.116864=23.098465}}}....round it

{{{23=23}}}