Question 1134782
Let integer one = x
Let integer two = y

x + y > 23
x = 3y - 5

Substitute the second inequality into the first, 

3y - 5 + y > 23
4y > 28
y>7

Since y>7, the least possible integer for y is 8:
x= 3(8)-5= 19

Least value: x = 19 and y = 8




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