Question 1134741
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Through (-3,-5) and perpendicular to x+2y=-4
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Slope of your given line is {{{-1/2}}}.
Slope for any line perpendicular to given line must be  {{{2}}}, which is negative reciprocal of {{{-1/2}}}.


Starting with point-slope form:
{{{y-(-5)=2(x-(-3))}}}
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{{{y+5=2(x+3)}}}
{{{y=2(x+3)-5}}}
{{{y=2x+6-5}}}
{{{highlight(y=2x+1)}}}-------finished in slope-intercept form