Question 1134678
{{{(x-3)/(x+2)-10/(x^2+2x)=0 }}}
{{{x(x-3)-10)=0}}}                   Multiplied {{{x^2+2x}}} on both sides.
{{{x^2-3x-10=0}}}
{{{(x-5)(x+2)=0}}}  
x=-2 and x=5

x cannot be -2 because we have (x+2) as the denominator. 

Otherwise, you will obtain error from the first part: (x-3)/(0)






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