Question 1134673
C( 5,2) = {{{ 5! / ( ( 5-2 )! * 2! )) }}}
C( 5,2 ) = {{{ ( 5*4*3*2*1 ) / (( 3*2*1 )*( 2*1  )) }}}
C( 5,2 ) = {{{ 120 / 12 }}}
C( 5,2 ) = {{{ 10 }}}
This is a combination problem because the order of
the 2 selections doesn't matter
The combinations with less than 15 yrs experience are:
3,6
3,7
3,10
6,7
There are {{{ 10 - 4 = 6 }}} combinations
that add up to at least {{{ 15 }}}
{{{ 6/10 = 3/5 }}} is the probability