Question 1134668
-----------------------------------------------
Determine weight of a block of marble, which contains 130.71 ft.^3 and specific gravity of 2.742. 
Density = Mass / Volume 
Unsure how to solve.
----------------------------------------------


Abbreviating,
{{{D=M/V}}}

and you are given D is 2.742 times that of water and V=130.71 cubic feet.
-------  The question asks for M.




Density for water is  about 1 gram per cubic centimeter.  You want to know or find the density of marble in POUNDS per CUBIC FOOT.


--

Density of water:


{{{1(gram/cm^3)*(1/453.59)(pounds/grams)*2.54^3*(cm/inch)^3*12^3*(inches/foot)^3}}}


{{{1(1/453.59)(2.54*12)^3}}}{{{pounds/foot^3}}}


{{{highlight_green(62.43(pounds/foot^3))}}}-----------density of water, in pounds per cubic foot.



Density of marble:


{{{62.43*2.742(pounds/foot^3)}}}

{{{highlight_green(171.2(pounds/foot^3))}}}


-


Finding the mass of the marble block:

{{{D=M/V}}}

{{{DV=M}}}

{{{M=DV}}}

{{{M=(171.2(pound/cubicfoot))(130.71*cubicfeet)}}}

{{{M=22380*pounds}}}