Question 1134551
there are 12 possibilities for the first turn.
there are 12 possibilities for the second turn.
there are 12 possibilities for the third and final turn.


the total possible numbers for the combination are 12 * 12 * 12 = 1728


to see how this works, assume only 2 numbers are possible for each turn.


let the numbers be 0 and 1.


you have 2 possibilities for the first turn and two possibilities for the second turn and two possibilities for the third and final turn.


total possibilities are 2 * 2 * 2 = 8.


those possibilities are:


000
001
010
011
100
101
110
111