Question 1134527
{{{system(f(x)=-2x+1,g(x)=x^2-2x-3)}}}


Find the zeros and the vertex of your parabola to help in graphing it.
{{{g(x)=x^2-2x-3}}}
{{{(x+1)(x-3)}}}
Zeros are at x {{{system(-1,and,3)}}}----------and since the vertex occurs in the exact middle, the x value for vertex must be at {{{x=1}}}; you can find the corresponding y value for this.


You can graph the given line f(x) since you already know its y-intercept and slope.